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Java Program to read from a file using FileInputStream and use available(), skip() to go through bytes – Q38
Q38: Java Program to read from a file using FileInputStream and use available(),skip() to go through bytes. Read ¼ n bytes on console, next ¼ n bytes on a byte array , and next ¼ n bytes skip and next ¼ n bytes again print it on console.
import java.io.*;
class FILE_AV_SK{
public static void main(String args[]) throws IOException{
int size;
InputStream f=new FileInputStream("tax.java");
size = f.available();
System.out.println("Total Available Bytes:" + size);
int n=size/4;
System.out.println("(1). First "+ n + " bytes of the file Displaying to Console");
for(int i=0;i<n;i++)
System.out.print((char) f.read());
System.out.println("\nStill Available: "+ f.available());
System.out.println("(2). Reading the next " + n +" and Storing to Byte Array.");
byte b[] = new byte[n];
for(int i=0; i<n; i++)
b[i] = (byte) f.read();
System.out.println("\nStill Available: "+(size = f.available()));
System.out.println("(3). Skipping half of remaining bytes with skip()");
f.skip(n);
System.out.println("Still Available: "+f.available());
System.out.println("(4). Last "+ n + " bytes of the file Displaying to Console");
for(int i=0;i<n;i++)
System.out.print((char) f.read());
f.close();
}
}
… from College notes (BCA/MCA assignments):
Categories: Java
Java File Handling, Java IO Programs
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