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Java Program to read from a file using FileInputStream and use available(), skip() to go through bytes – Q38
Q38: Java Program to read from a file using FileInputStream and use available(),skip() to go through bytes. Read ¼ n bytes on console, next ¼ n bytes on a byte array , and next ¼ n bytes skip and next ¼ n bytes again print it on console.
import java.io.*; class FILE_AV_SK{ public static void main(String args[]) throws IOException{ int size; InputStream f=new FileInputStream("tax.java"); size = f.available(); System.out.println("Total Available Bytes:" + size); int n=size/4; System.out.println("(1). First "+ n + " bytes of the file Displaying to Console"); for(int i=0;i<n;i++) System.out.print((char) f.read()); System.out.println("\nStill Available: "+ f.available()); System.out.println("(2). Reading the next " + n +" and Storing to Byte Array."); byte b[] = new byte[n]; for(int i=0; i<n; i++) b[i] = (byte) f.read(); System.out.println("\nStill Available: "+(size = f.available())); System.out.println("(3). Skipping half of remaining bytes with skip()"); f.skip(n); System.out.println("Still Available: "+f.available()); System.out.println("(4). Last "+ n + " bytes of the file Displaying to Console"); for(int i=0;i<n;i++) System.out.print((char) f.read()); f.close(); } }
… from College notes (BCA/MCA assignments):
Categories: Java
Java File Handling, Java IO Programs
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